2×2x2 - Layer-by-Layer
1st layer:
You’re on your own here. If you can solve the 3×3x3, then you should have no problem doing this. Must be correctly oriented and permuted.
2nd layer:
Think of it as a 3×3x3 without the edges. So it’s just OLL - you can run into the following cases (use the inverse algorithm if you don’t see the case):
| Case | Algorithm | Alt. Case | Alt. Algorithm |
|---|---|---|---|
| R2 U2 R’ U2 R2 | |||
| R U2 R2 U’ R2 U’ R2 U2 R | |||
| R’ U2 R U R’ U R | |||
| R U2 R’ U’ R U’ R’ | |||
| F R U R’ U’ F’ | F R’ U’ R U F’ | ||
| R’ F’ L F R F’ L’ F | R U R’ U’ L’ U R U’ | ||
| R’ F’ L’ F R F’ L F | F R U’ R’ U’ R U R’ F’ |
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PLL - You only have 3 cases (one of which is the solved state):
| Case | Algorithm |
|---|---|
| R U2 R’ U’ R U2 L’ U R’ U’ L | |
| F R U’ R’ U’ R U R’ F’ R U R’ U’ L’ U R U’ |
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